admin Password: ' = '
SELECT user_id FROM users WHERE username = 'admin' = '1' AND password = '<pass>'
For every single quote ( ' ) found in the user input string, the function replaces it with an escaped variant: \' .
Let's examine the mechanics of the exploit in more detail. Sql Injection Challenge 5 Security Shepherd
Here are a few payloads that consistently work:
admin' * IF(1, SLEEP(5), 0) -- -
:
This is the most common solution mentioned online. The injected password turns the query's password check into an always-true condition, allowing a successful login as administrator.
username=admin&password=test
using the requests library to solve it without SQLMap admin Password: ' = ' SELECT user_id FROM
: Acts as the closing delimiter for the data string, closing out the code value.
String query = "SELECT * FROM users WHERE username = ?"; PreparedStatement pstmt = connection.prepareStatement(query); pstmt.setString(1, userInput); // Safe parameterization ResultSet resultSet = pstmt.executeQuery(); Use code with caution. 2. Implement the Principle of Least Privilege
Security Researcher Date: April 11, 2026 Subject: Web Application Security / SQL Injection (Level: Intermediate) The injected password turns the query's password check